Answer:
[tex]FS = 2.773[/tex]
Explanation:
A possible approach is using Von Mises Yield Criterion, which convert such stresses into an equivalent normal stress. The formula for any beam or rod is:
[tex]\sigma_{VM} =\sqrt{\sigma_{axial}^{2}+3\cdot \tau_{torsion}^{2}}[/tex]
The equivalent stress for the studied rod is:
[tex]\sigma_{VM} = \sqrt{(50\,MPa)^{2}+3\cdot (100\,MPa)^{2}}[/tex]
[tex]\sigma_{VM} \approx 180.278\,MPa[/tex]
Safety factor is:
[tex]FS=\frac{\sigma_{y}}{\sigma_{VM}}[/tex]
[tex]FS = 2.773[/tex]
