Explanation:
It is known that relation between pressure and density is as follows.
P = [tex]\rho gh[/tex]
where, P = pressure
[tex]\rho[/tex] = density
g = acceleration due to gravity
h = height
Putting the given values into the above formula as follows.
P = [tex]\rho gh[/tex]
= [tex]1025 \times 9.8 \times 11000[/tex]
= 110495000 Pa
Now, relation between pressure and force is as follows.
P = [tex]\frac{F}{A}[/tex]
or, F = PA
F = [tex]110495000 \times \pi \times (0.1)^{2}[/tex]
= [tex]3.47 \times 10^{6} N[/tex]
Thus, we can conclude that a force of [tex]3.47 \times 10^{6} N[/tex] can be experienced at such depth.
