Two cars have identical horns, each emitting a frequency of fs = 406 Hz. One of the cars is moving with a speed of 10.5 m/s toward a bystander waiting at a corner, and the other car is parked. The speed of sound is 343 m/s. What is the beat frequency heard by the bystander?

Respuesta :

Answer:

[tex]f_{B}=12.8 Hz[/tex]

Explanation:

Let's start finding the frequency heard by the bystander due to the moving car. We need to use Doppler effect here:

[tex]f_{obs}=f_{s}\left(\frac{v}{v-v_{car}}\right)[/tex]    

v is the speed of sound (v = 343 m/s)  

So, we have:

[tex]f_{obs}=406\left(\frac{343}{343-10.5}\right)=418.8 Hz[/tex]                  

Now, the beat frequency heard by the bystander is the combine of the frequencies, it means the difference between them. Therefore the equation is given by:

[tex]f_{B}=f_{obs}-f_{s}=418.8-406=12.8 Hz[/tex]    

I hope it helps you!