Answer:
67.38 Hz
Explanation:
Using,
F = 1/(2L)[√(T/ρ)].............. Equation 1
Where F = fundamental frequency of the string, L= length of the string, T = Tension in the string, ρ = density of the string.
Given: L = 361 cm = 3.61 m, ρ = 0.039 g/cm = 0.0039 kg/m, T = 923 N.
Substitute into equation 1
F = 1/(2×3.61)[√(923/0.0039)]
F = 1/7.22(√236666.67)
F = 1/7.22(486.48)
F = 67.38 Hz
Hence the fundamental frequency of the string = 67.38 Hz
