Answer:
y = 50°
Step-by-step explanation:
Diagonals of a kite intersect at right angles.
[tex] \angle ABD = 180° - (90° + 40°)\\\\
\therefore \angle ABD = 180° - 130°\\\\
\therefore \angle ABD = 50°\\[/tex]
Diagonal BD bisects [tex]\angle ABC[/tex]
[tex]\therefore \angle ABD = \angle CBD = 50°\\\\
\huge \red {\boxed {\therefore y = 50°}} [/tex]
