Respuesta :
Answer:
Explanation:
mass of line backer, m1 = 110 kg
mass of half back, m2 = 85 kg
initial velocity of line backer, u1 = 8.8 m/s north = 8.8 j
initial velocity of the half back, u2 = 7.2 m/s east = 7.2 i
Use conservation of momentum
m1 x u1 + m2 x u2 = (m1 + m2) x v
where, v is the velocity of the combined mass
110 x 8.8 j + 85 x 7.2 i = (110 + 85) x v
968 j + 612 i = 195 v
v = 4.96 j + 3.14 i
The magnitude of velocity is
[tex]v=\sqrt{4.96^{2}+3.14^{2}}[/tex]
v = 5.87 m/s
[tex]tan\theta = \frac{4.96}{3.14}[/tex]
θ = 57.7°
