156 g C12H22O11 (sucrose) is dissolved into 4.0 L of solution. What is the molar concentration of the solution? Report your answer with the correct number of significant figures.

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Answer:

The molar concentration is 0.114 M (≈0.11 M)

Explanation:

Step 1: Data given

Mass of sucrose = 156 grams

Molar mass of sucrose = 342.3 g/mol

Volume = 4.0 L

Step 2: Calculate moles sucrose

Moles sucrose = mass sucrose / molar mass sucrose

Moles sucrose = 156 grams / 342.3 g/mol

Moles sucrose = 0.456 moles

Step 3: Calculate molar concentration of the solution

Concentration of solution = moles sucrose / volume

Concentration of solution = 0.456 moles / 4.0 L

Concentration of solution = 0.114 M

The molar concentration is 0.114 M (≈0.11 M)

Answer:

The molar concentration of the solution is [tex]0.114 M[/tex]

Explanation:

Molar concentration is the density of the substance per unit volume of particular solute in a solution.

Given:

Mass of sucrose [tex]= 156 g[/tex]

Molar mass of sucrose[tex]= 342.3 g/mol[/tex]

Volume[tex]= 4.0 L[/tex]

Step 1:

To find the moles of sucrose

[tex]= \frac{mass\ of \ sucrose}{molar\ mass\ of\ sucrose}[/tex]

[tex]= \frac{156 g}{342.3g/mol}[/tex]

[tex]= 0.456 moles[/tex]

Step 2:

Calculate the molar concentration of the solution

[tex]=\frac{moles\ of\ sucrose}{volume}[/tex]

[tex]= \frac{0.456moles}{4.0L}[/tex]

[tex]= 0.114 M[/tex]

Therefore, the molar concentration is [tex]0.114 M[/tex]

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