Answer:
[tex]\sqrt{2\cdot 17}[/tex]
Step-by-step explanation:
The magnitude of a vector is the length of the vector itself.
Given a bi-dimensional vector, the magnitude of the vector is given by:
[tex]|v|=\sqrt{v_x^2+v_y^2}[/tex]
where
[tex]v_x[/tex] is the x-component of the vector
[tex]v_y[/tex] is the y-component of the vector
The vector in this problem is
[tex]v=(-5,3)[/tex]
Therefore its components are
[tex]v_x=-5\\v_y=3[/tex]
And so, the magnitude of the vector is:
[tex]|v|=\sqrt{(-5)^2+(3)^2}=\sqrt{25+9}=\sqrt{34}=\sqrt{2\cdot 17}[/tex]
