Step-by-step explanation:
[tex]x + 2y = 6....(1) \\ \\ x - 4y = 0\\ \implies \: x = 4y....(2)\\ \\ from \: equations \: (1) \: and \: (2) \\ 4y + 2y = 6 \\ \therefore \: 6y = 6 \\ \\ \therefore \: y = \frac{6}{6} \\ \\ \huge \red{ \boxed{ \therefore \: y = 1}} \\ \\ substituting \: y = 1 \: in \: equation \: (2) \\ \\ x = 4y \\ \\ \therefore \: x = 4 \times 1 \\ \\ \huge \orange{ \boxed{\therefore \: x = 4 }} \\ \\ \therefore \: (x, \: \: y) = (4, \: \: 1) \\ is \: the \: required \: solution. \\ [/tex]
