Answer:
The concentration of the HCOOH solution is 0.1958 M
Explanation:
Step 1: Data given
Concentration of HCOOH = 0.20 M
Concentration of NaOH = 0.1105 M
We add 20.00 mL of HCOOH to the beaker before titrating, and it requires 35.43 mL of NaOH to reach the end point
Step 2: The balanced equation
HCOOH + NaOH → HCOONa + H2O
Step 3: Calculate moles of NaOH
Moles of NaOH = molarity * volume
Moles of NaOH = 0.1105M * 0.03543 L = 0.003915moles
Step 4: Calculate moles HCOOH
For 1 mol HCOOH we need 1 mol NaOH to produce 1 mol HCOONa and 1 mol H2O
For 0.003915 moles NaOH we need 0.003915 moles HCOOH
Step 5: Calculate concentration of HCOOH
Concentration of HCOOH = moles HCOOH / volume
Concentration of HCOOH = 0.003915 moles / 0.020 L
Concentration of HCOOH = 0.1958 M
The concentration of the HCOOH solution is 0.1958 M