Answer:
Explanation:
radius of the solenoid, r = 0.05 m
length of the solenoid, l = 0.39 m
Magnetic field of the solenoid, B = 2 x 10^-5 T
Number of turns, N = 200
The magnetic field of the solenoid is given by
[tex]B=\mu _{0}ni[/tex]
where, i be the current and n be the number of turns per unit length
n = N / l = 200 / 0.39 = 512.8
[tex]2\times 10^{-5}=4 \times 3.14\times 10^{-7}\times 512.8\times i[/tex]
i = 0.031 A
