Answer:
The final velocity of the system is 0.304 m/s.
Explanation:
Given that,
Mass of the 1 clay model, [tex]m_1=0.25\ kg[/tex]
Mass of the second clay model, [tex]m_2=0.325\ kg[/tex]
Initial speed of the first clay model, [tex]u_1=0.7\ m/s[/tex]
Initial speed of the second clay model, [tex]u_2=0[/tex] (at rest)
Both being soft clay, they naturally stick together. It is a case of inelastic collision. The momentum of the system remains conserved such that :
[tex]m_1u_1+m_2u_2=(m_1+m_2)V[/tex]
V is the final velocity of the system
[tex]V=\dfrac{m_1u_1}{(m_1+m_2)}\\\\V=\dfrac{0.25\times 0.7}{(0.25+0.325)}\\\\V=0.304\ m/s[/tex]
So, the final velocity of the system is 0.304 m/s. Hence, this is the required solution.
