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A diver makes 0.50 revolutions on the way from a 9.4-m-high platform to the water. Assuming zero initial vertical velocity, find the diver's average angular velocity during a dive.

Respuesta :

Answer:

Explanation:

wi = 0 rad/s

Theta = 0.5 rev

r = 9.4 m

S = 2 × pi × theta × r

= 2pi × 0.5 × 9.4

= 29.53 m

at × r = g

= 1.043 rad/s^2

Using angular equation of motion,

wf^2 = wi^2 + 2× at × S

wf^2 = 2 × 1.043 × 29.53

= 7.85 rad/s

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