Cody wants to attend the fall festival at school. The price of admission to the festival is $5.50 and each game costs an additional $0.75 cents if Cody has $15.00 to spend at the festival, which inequality can be used to solve for g, the number of games that he can play, what is the maximum number of games he can play?

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gymnast91 gymnast91 · Answer 1 · 2020-03-09T19:13:50+01:00

Cody can play up to 10 games! Hope this helps, if it does please mark BRAINLIEST

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ashishdwivedilVT ashishdwivedilVT · Answer 2 · 2022-04-15T13:29:25+02:00

The maximum number of games Cody can play is 12.

Admission price = $5.50

Additional cost for each game = $0.75

Suppose Cody plays x games

So, x games will additionally cost $0.75x

Total cost for Cody =$(5.50 +0.75x)

Amount of money with Cody = $15

Inequality is a relation that makes a non-equal comparison between two numbers.

The total cost for Cody must be equal to or less than the amount of money with Cody.

This means [tex]5.50 +0.75x\leq 15[/tex]

So the required inequality is [tex]5.50 +0.75x\leq 15[/tex].

So the maximum number of games Cody can play will be:

[tex]5.50 +0.75x=15\\0.75x = 9.5\\x=12.66[/tex]

x≈12

Hence, the required inequality is [tex]5.50 +0.75x\leq 15[/tex] and the maximum number of games Cody can play is 12.

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