Answer:
Concentration = 3.105 mol/L
Explanation:
To determine the concentration of a solution it can be identified by means of the Molarity equation:
[tex]M=\frac{# mol}{volume (L)}[/tex]
Milliliters to liters are converted:
2510 mL = 2.150 L
[tex]mol=\frac{mass (g)}{MW}[/tex]
The molecular weight of Li2SO4 is determined for the calculation of moles:
[tex]mol=\frac{734g}{109.94g/mol}=6.6764mol[/tex]
[tex]M=\frac{6.6764mol}{2.15 L}=3.105 \frac{mol}{L}[/tex]
Answer: 2.66 M
Explanation:
The molecular mass of Li2SO4 is 109.94 g/mol
Calculate moles:
734 g109.94 g/mol=6.68 mol
Calculate molarity:
M= 6.68 mol / 2.51 L
= 2.66 M
