Answer:
198 pages have no mistakes.
Step-by-step explanation:
We are given the following in the question:
The number of mistakes on a page follows a poison distribution with
[tex]\mu = \lambda = 0.01[/tex]
Formula:
[tex]P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}[/tex]
We have to find the probability that there are no mistakes on a page.
[tex]P(X =0) = \displaystyle\frac{(0.01)a^0 e^{-0.01}}{0!} = 0.9901[/tex]
Thus, approximately 99.01% of the pages have no mistakes.
Number of pages =
[tex]\text{Total number of pages}\times 99.01\%\\\\200\times \dfrac{99.01}{100}\\\\\approx 198[/tex]
Thus, 198 pages have no mistakes.
