Answer:
(a) 0.932
(b) 0.0653
(c) 0.032
(d) 0.316
(e) 0.251
Step-by-step explanation:
From the table with mean parameter μ = 5, we can compute the following cumulative and density probability
(a) [tex]P(X \leq 8) = 0.932[/tex] (cumulative)
(b) P(X = 8) = 0.0653 (density)
(c) [tex] P(9 \leq X) = 1 - P(X \leq 9) = 1 - 0.968 = 0.032[/tex] (cumulative)
(d) [tex]P(5 \leq X \leq 8) = P(X \leq 8) - P(X \leq 5) = 0.932 - 0.616 = 0.316 [/tex] (cumulative)
(e) [tex]P(5 < X < 8) = P(X \leq 8) - P(X \leq 5) - P(X = 8) = 0.932 - 0.616 - 0.0653 = 0.251 [/tex]