Answer:
a) [tex]L=40295.31\times 10^{-7} H=4.0295\ mH[/tex]
b) [tex]E=5.0571\ J[/tex]
Explanation:
Given:
a)
The inductance of the solenoid is given as:
[tex]L=\frac{\mu.N^2.A}{l}[/tex]
where:
[tex]\mu=[/tex] permeability of the free space [tex]=4\pi\times 10^{-7}\ T.m.A^{-1}[/tex]
[tex]A=[/tex] cross sectional area of coil formed
[tex]L=\frac{(4\pi\times 10^{-7})\times295^2 \times(\pi\times 0.0525^2)}{0.235}[/tex]
[tex]L=40295.31\times 10^{-7} H=4.0295\ mH[/tex]
b)
current in the coil, [tex]I=0.501\ A[/tex]
The energy stored in the solenoid can be given as:
[tex]E=\frac{1}{2}\times L.I^2[/tex]
[tex]E=0.5 \times 4.0295\times 10^{-3}\times 0.501^2[/tex]
[tex]E=5.0571\ J[/tex]
