contestada

1. The inlet section of a vacuum cleaner is a rectangle, 1 in by 5 in. The blower is able to provide suction at 25 cubic feet per minute. (a) What is the average velocity at the inlet, in m/s

Respuesta :

Answer:

average velocity at the inlet = 3.66 m/s

Explanation:

given data

discharge Q =  25 ft³ /min = [tex]\frac{25}{60}[/tex]  = 0.417 ft³  

vacuum cleaner = 1 in by 5 in = [tex]\frac{1}{12} \ by\ \frac{5}{12}[/tex]   ft

solution

we know discharge that is express as

Q = Area × Velocity   .............1

put here value and we will get  average velocity at the inlet

average velocity at the inlet = [tex]\frac{0.417}{\frac{1}{12} \frac{5}{12} }[/tex]  

average velocity at the inlet = 3.66 m/s

Answer:

The average velocity at the inlet is 3.66 m/s.

Explanation:

Given that,

Width = 1 in

Length = 5 in

Flow rate = 25 feet³/m

We need to calculate the average velocity at the inlet

Using formula of velocity at the inlet

[tex]v_{in}=\dfrac{Q}{A_{in}}[/tex]

Where, Q = flow rate

A = area

Put the value into the formula

[tex]v_{in}=\dfrac{\dfrac{25}{60}}{\dfrac{1}{12}\times\dfrac{5}{12}}[/tex]

[tex]v_{in}=12\ ft/s[/tex]

[tex]v_{in}=12\times0.3048[/tex]

[tex]v_{in}=3.66\ m/s[/tex]

Hence, The average velocity at the inlet is 3.66 m/s.