Answer:
The distance from the base of the statue to the ship is 771.60 ft
Step-by-step explanation:
Refer the attached figure
Height of statue AB= 250 feet
The tourist sees a ship coming into the harbor and measures the angle of depression as 18°.
So, ∠ACB = 18°
We are supposed to find the distance from the base of the statue to the ship i.e. BC
In ΔABC
[tex]Tan \theta = \frac{Perpendicular}{Base}[/tex]
[tex]Tan 18^{\circ}=\frac{AB}{BC}[/tex]
[tex]Tan 18^{\circ}=\frac{250}{BC}[/tex]
[tex]BC=\frac{250}{Tan 18^{\circ}}[/tex]
[tex]BC=\frac{250}{0.324}[/tex]
BC=771.60 ft
Hence the distance from the base of the statue to the ship is 771.60 ft
