Answer:
The energy of one photon of this microwave radiation is [tex]1.56\times 10^{-24}\ J[/tex].
Explanation:
Given that,
Wavelength of the microwave, [tex]\lambda=12.7\ cm=12.7\times 10^{-2}\ m[/tex]
We need to find the energy of exactly one photon of this microwave radiation. We know that the energy of a photon is given by the formula as :
[tex]E=\dfrac{nhc}{\lambda}\\\\E=\dfrac{1\times 6.63\times 10^{-34}\times 3\times 10^8}{12.7\times 10^{-2}}\\\\E=1.56\times 10^{-24}\ J[/tex]
So, the energy of one photon of this microwave radiation is [tex]1.56\times 10^{-24}\ J[/tex]. Hence, this is the required solution.
