Twin A makes a one way trip at 0.6c to a star 12 light years away while twin B stays on Earth. Each twin sends the other a signal once a year by his own time. (a) How many signals does A send during the trip

Respuesta :

Answer:

8 signals received by twin A during the trip.

Explanation:

Given that,

Distance = 12 light year

Speed = 0.6 c

Time = 1 year

We need to calculate the time by A

Using formula of time

[tex]T=t\sqrt{\dfrac{1+\dfrac{v}{c}}{1-\dfrac{v}{c}}}[/tex]

Put the value into the formula

[tex]T=1\sqrt{\dfrac{1+0.6}{1-0.6}}[/tex]

[tex]T=2\ years[/tex]

Similarly,

The expression for distance cover by A

[tex]D=d\sqrt{1-\dfrac{v^2}{c^2}}[/tex]

[tex]D=12\sqrt{1-(0.6)^2}[/tex]

[tex]D=9.6\ ly[/tex]

We need to calculate the time

Using formula of time

[tex]t=\dfrac{D}{v}[/tex]

[tex]t=\dfrac{9.6}{0.6}[/tex]

[tex]t=16\ years[/tex]

We need to calculate the signals received by twin A

Using formula for number of signals

[tex]n=\dfrac{t}{T}[/tex]

Put the value into the formula

[tex]n=\dfrac{16}{2}[/tex]

[tex]n=8\ signals[/tex]

Hence, 8 signals received by twin A during the trip.