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The body metabolizes glucose (C6H12O6) by burning it with oxygen to produce carbon dioxide, water and energy. If 3 moles of glucose are burned, what volume of CO2 (g) is produced at STP

Respuesta :

Answer: 18g

Explanation:

1 mle of glucose combusts to give 6moles of CO2 and 6moles of H2O

C6H12O6 + 6O2-------- 6CO2 + 6H2O at STP.

Multiplying 6 by 3 moles we have 18 g of CO2

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