two cranes, one is 24.3 degree with the horizontal and another is 44.5 degrtees with the horizontal, are lifting an object that weighs 20,240 pounds. find the tension in the cable opf each crane.

Respuesta :

Answer:

Explanation:

Weight, W = 20240 lbs

Let the tension in one cable is P and in another cable is Q.

α = 24.3°, β = 44.5°

Use Lami's theorem

[tex]\frac{P}{Sin(90+44.5)}=\frac{Q}{Sin(90+24.3)}=\frac{W}{Sin(180-44.5-24.3)}[/tex]

[tex]\frac{P}{Sin(134.5)}=\frac{Q}{Sin(114.3)}=\frac{20240}{Sin(111.2)}[/tex]

[tex]P=\frac{20240\times Sin 134.5}{Sin(111.2)}=\frac{14436.19}{0.93}[/tex]

P = 15484.1 lbs

[tex]Q=\frac{20240\times Sin 114.3}{Sin(111.2)}=\frac{18446.8}{0.93}[/tex]

Q = 19835.3 lbs