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The friends consider a block of mass 1.1 kg set in motion by an external force. The initial velocity is 1.6 m/s, and the coefficient of kinetic friction is 0.03. What do they find as the final change in internal energy of the system once the block comes to a complete stop

Respuesta :

Explanation:

The given data is as follows.

         Final K.E = 0,    

and,    Initial K.E = [tex]\frac{1}{2}mv^{2}[/tex]

So, we will calculate the initial kinetic energy as follows.

         Initial K.E = [tex]\frac{1}{2}mv^{2}[/tex]      

                       = [tex]\frac{1}{2} \times 1.1 kg \times (1.6)^{2}[/tex]

                       = 1.408 J

Now, we will calculate the change in kinetic energy as follows.

        [tex]\Delta K.E[/tex] = Final K.E - Initial K.E

                      = 0 - 1.408 J

Thus, we can conclude that the change in kinetic energy is 1.408 J.

onyebuchinnaji

The change in the internal energy of the system is 1.408 J.

The given parameters;

  • mass of the given block, m = 1.1 kg
  • initial velocity of the block, u = 1.6 m/s
  • coefficient of friction, μ = 0.03

The change in the internal energy of the system is calculated as follows;

[tex]\Delta U = \Delta K.E - \ P.E\\\\\Delta U = \frac{1}{2} (1.1)(1.6^2) - (0)\\\\\Delta U = 1.408 \ J[/tex]

Thus, the change in the internal energy of the system is 1.408 J.

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