Respuesta :
Answer:
Molarity of NaCl = Molarity of sodium ions = Molarity of chloride ions = 0.01 M
Explanation:
Considering
[tex]Molarity_{diluted\ solution}\times Volume_{diluted\ solution}=Molarity_{stock\ solution}\times Volume_{stock\ solution}[/tex]
Given that:
[tex]Molarity_{diluted\ solution}=?[/tex]
[tex]Volume_{diluted\ solution}=10\ mL[/tex]
[tex]Volume_{stock\ solution}=2\ mL[/tex]
[tex]Molarity_{stock\ solution}=0.05\ M[/tex]
So,
[tex]Molarity_{diluted\ solution}\times 10\ mL=0.05\ M\times 2\ mL[/tex]
[tex]Molarity_{diluted\ solution}=0.01\ M[/tex]
Molarity of NaCl = Molarity of sodium ions = Molarity of chloride ions = 0.01 M
The total concentration of ions in the diluted solution is Molarity of NaCl = Molarity of sodium ions = Molarity of chloride ions = 0.01 M.
Calculation of the total concentration:
Since
molarity of diluted solution * volume of diluted solution = molarity of stock solution * volume of stock solution
Here,
volume of diluted solution = 10 mL
Volume of stock solution = 2 mL
And, the molarity of stock solution = 0.05 M
So, the molarity of diluted solution is
= 0.05 M * 2 mL / 10 mL
= 0.01 m
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