A permeability test was run on a compacted sample of dirty sandy gravel. The sample was 175 mm long and the diameter of the mold 175 mm. In 90 s the discharge under a constant head of 38 em was 405 cm3 The sample had a dry mass of 4950 g and its Ps was 2710 kg!m3 Calculate (a) the coefficient of permeability, (b) the seepage velocity, and (c) the discharge velocity during the test.

Respuesta :

Answer:

(a). The coefficient of permeability is [tex]8.6\times10^{-3}\ cm/s[/tex].

(b). The seepage velocity is 0.0330 cm/s.

(c). The discharge velocity during the test is 0.0187 cm/s.

Explanation:

Given that,

Length = 175 mm

Diameter = 175 mm

Time = 90 sec

Volume= 405 cm³

We need to calculate the discharge

Using formula of discharge

[tex]Q=\dfrac{V}{t}[/tex]

Put the value into the formula

[tex]Q=\dfrac{405}{90}[/tex]

[tex]Q=4.5\ cm^3/s[/tex]

(a). We need to calculate the coefficient of permeability

Using formula of coefficient of permeability

[tex]Q=kiA[/tex]

[tex]k=\dfrac{Q}{iA}[/tex]

[tex]k=\dfrac{Ql}{Ah}[/tex]

Where, Q=discharge

l = length

A = cross section area

h=constant head causing flow

Put the value into the formula

[tex]k=\dfrac{4.5\times175\times10^{-1}}{\dfrac{\pi(175\times10^{-1})^2}{4}\times38}[/tex]

[tex]k=8.6\times10^{-3}\ cm/s[/tex]

The coefficient of permeability is [tex]8.6\times10^{-3}\ cm/s[/tex].

(c). We need to calculate the discharge velocity during the test

Using formula of discharge velocity

[tex]v=ki[/tex]

[tex]v=\dfrac{kh}{l}[/tex]

Put the value into the formula

[tex]v=\dfrac{8.6\times10^{-3}\times38}{17.5}[/tex]

[tex]v=0.0187\ cm/s[/tex]

The discharge velocity during the test is 0.0187 cm/s.

(b). We need to calculate the volume of solid in the ample

Using formula of volume

[tex]V_{s}=\dfrac{M_{s}}{V_{s}}[/tex]

Put the value into the formula

[tex]V_{s}=\dfrac{4950\times10^{-3}}{2710}[/tex]

[tex]V_{s}=1826.56\ cm^3[/tex]

We need to calculate the volume of the soil specimen

Using formula of volume

[tex]V=A\times L[/tex]

Put the value into the formula

[tex]V=\dfrac{\pi(17.5)^2}{4}\times17.5[/tex]

[tex]V=4209.24\ cm^3[/tex]

We need to calculate the volume of the voids

[tex]V_{v}=V-V_{s}[/tex]

Put the value into the formula

[tex]V_{v}=4209.24-1826.56[/tex]

[tex]V_{v}=2382.68\ cm^3[/tex]

We need to calculate the seepage velocity

Using formula of velocity

[tex]Av=A_{v}v_{s}[/tex]

[tex]v_{s}=\dfrac{Av}{A_{v}}[/tex]

[tex]v_{s}=\dfrac{V}{V_{v}}\times v[/tex]

Put the value into the formula

[tex]v_{s}=\dfrac{4209.24}{2382.68}\times0.0187[/tex]

[tex]v_{s}=0.0330\ cm/s[/tex]

The seepage velocity is 0.0330 cm/s.

Hence, (a). The coefficient of permeability is [tex]8.6\times10^{-3}\ cm/s[/tex].

(b). The seepage velocity is 0.0330 cm/s.

(c). The discharge velocity during the test is 0.0187 cm/s.