Answer: The required value is -1.
Step-by-step explanation:
Since we have given that
[tex]\lim_{x \to 1} x^2+3x-4x^2-1[/tex]
Since , it is necessary to rewrite the expression before limit properties as there is like terms exists.
[tex]f(x)=x^2+3x-4x^2-1\\\\f(x)=-3x^2+3x-1[/tex]
So, it becomes,
[tex]\lim_{x \to 1} (-3x^2+3x-1)=-3(1)^2+3(1)-1=-3+3-1=-1[/tex]
Hence, the required value is -1.