Answer:
Resultant force = 17.02 N
Explanation:
As we assume the coefficient of friction is negligible, the normal force won't affect the resultant force.
As a result of this, the sine of the angle times the force of gravity on the 10 kg mass is equal to the resultant force, which is, force due to gravity = m × a = 10 kg × 9.8 m/s² = 98 N
98 sin(10)=?
Sin(10)= 0.1736
98 x 0.1736= 17.02 N.
Therefore, the resultant force = 17.02 N
The resultant force on the sled is 17.02 N and this can be determined by using Newton's second law of motion
Given :
A 10-kg mass slides down a flat hill that makes an angle of 10° with the horizontal.
First, determine the force by using Newton's second law of motion.
F = ma
F = 10 [tex]\times[/tex] 9.8
F = 98N
Now, the resultant force on the sled can be calculated as:
[tex]\rm F_R = F sin\theta[/tex]
Now, substitute the known terms in the above expression.
[tex]\rm F_R = 98\times sin10[/tex]
Simplify the above expression in order to determine the value of [tex]\rm F_R[/tex].
[tex]\rm F_R[/tex] = 17.02 N
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https://brainly.com/question/2996858