Answer:
[tex]3.83\Omega[/tex]
Explanation:
Resistors are said to be connected in parallel when they have they are connected into separate branches and they have the same potential difference across them.
In this case, the equivalent resistance of N resistors in parallel is:
[tex]\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+...+\frac{1}{R_N}[/tex]
In this problem, we have three resistors in parallel, so the equivalent resistance is given by:
[tex]\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}[/tex]
Where:
[tex]R_1=20.0 \Omega[/tex]
[tex]R_2=10.0 \Omega[/tex]
[tex]R_3=9.00 \Omega[/tex]
Therefore, the equivalent resistance of this circuit is:
[tex]\frac{1}{R}=\frac{1}{20}+\frac{1}{10}+\frac{1}{9}=0.261\\R=\frac{1}{0.261}=3.83\Omega[/tex]
