Answer:
The gas obeys Boyle’s law and the value of [tex]k_i\&k_f[/tex] both are equal to 40.0 atm L.
Explanation:
Initial volume of the gas = [tex]V_1=10.0 L[/tex]
Initial pressure of the gas = [tex]P_1=4.0 atm[/tex]
Final volume of the gas = [tex]V_2=5.0 L[/tex]
Final pressure of the gas = [tex]P_2=8.0 atm[/tex]
This law states that pressure is inversely proportional to the volume of the gas at constant temperature.
[tex]PV=k[/tex]
The equation given by this law is:
[tex]P_1V_1=P_2V_2[/tex]
[tex]P_1\propto \frac{1}{V_1}[/tex]
[tex]P_1V_1=k_i[/tex]
[tex]k_i=4.0 atm\times 10.0 L = 40.0 atm L[/tex]
[tex]P_2\propto \frac{1}{V_2}[/tex]
[tex]P_V_2=k_f[/tex]
[tex]k_f=8.0 atm\times 5.0 L = 40.0 atm L[/tex]
[tex]k_i=k_f=40.0 atm L[/tex]
The gas in the cylinder is obeying Boyle's law.
The gas obeys Boyle’s law and the value of [tex]k_i\&k_f[/tex] both are equal to 40.0 atm L.
