Answer:
Magnetic field at the center of the loop [tex]B=5.89\times 10^{-5}\ T.[/tex]
Explanation:
It is given that total length of wire is 2 m and number of circular loop is 5 turns.
Therefore ,
[tex]5\times ( 2\pi r)=2 \ m .\\\\r=\dfrac{1}{5 \pi}=0.064\ m.[/tex]
We know , magnetic field at the center of loop is given by :
[tex]B=N\dfrac{\mu_o i}{2r}[/tex]
Putting all values in above equation we get :
[tex]B=5\times \dfrac{4\pi\times 10^{-7}\times 1.2}{2\times 0.064}\\\\B=5.89\times 10^{-5}\ T.[/tex]
Hence , this is the required solution.
