Answer:
The force of gravity between the newborn baby and Mars is [tex]3.94x10^{-8}N[/tex]
Explanation:
The universal law of gravitation is defined as:
[tex]F = G\frac{m1m2}{r^{2}}[/tex] (1)
Where G is the gravitational constant, m1 and m2 are the masses of the two objects and r is the distance between them.
Since the newborn baby is at the Earth, it will be at a distance (r) of [tex]5.6x10^{10}m[/tex] from Mars.
Therefore, equation 1 can be used:
[tex]F = (6.67x10^{-11}kg.m/s^{2}.m^{2}/kg^{2})\frac{(2.9Kg)(6.4x10^{23}Kg)}{(5.6x10^{10}m)^{2}}[/tex]
[tex]F = 3.94x10^{-8}Kg.m/s^{2}[/tex]
[tex]F = 3.94x10^{-8}N[/tex]
Hence, the force of gravity between the newborn baby and Mars is [tex]3.94x10^{-8}N[/tex].
