Answer:
The ration of formation of ammonia gas is 0.01067 M/s.
Explanation:
[tex]N_2(g) + 3H_2(g)\rightarrow 2NH_3(g)[/tex]
Rate of the reaction = R
[tex]R=\frac{-1}{1}\frac{d[N_2]}{dt}=\frac{-1}{3}\frac{d[H_2]}{dt}=\frac{1}{2}\frac{d[NH_3]}{dt}[/tex]
Rate at which hydrogen gas is reacting = [tex]-\frac{d[H_2]}{dt}=0.0160M/s[/tex]
Rate at which ammonia gas is forming = [tex]-\frac{d[NH_3]}{dt}[/tex]
[tex]\frac{-1}{3}\frac{d[H_2]}{dt}=\frac{1}{2}\frac{d[NH_3]}{dt}[/tex]
[tex]\frac{-1}{3}\frac{d[H_2]}{dt}\times 2=\frac{d[NH_3]}{dt}[/tex]
[tex]\frac{1}{3}(-\frac{d[H_2]}{dt})\times 2=\frac{d[NH_3]}{dt}[/tex]
[tex]\frac{2}{3}\times 0.0160M/s=0.01067 M/s[/tex]
The ration of formation of ammonia gas is 0.01067 M/s.
