Answer:
The speed of the electron is [tex]2.55\times 10^3\ m/s[/tex].
Explanation:
Given that,
The magnitude of electric field, [tex]E=1.32\ kV/m=1.32\times 10^3\ V/m[/tex]
The magnitude of magnetic field, B = 0.516 T
Both the magnetic and electric fields are acting on the moving electron. Then, the magnitude of electric field and magnetic field is balanced such that :
[tex]evB=eE\\\\v=\dfrac{E}{B}\\\\v=\dfrac{1.32\times 10^3}{0.516}\\\\v=2558.13\ m/s[/tex]
or
[tex]v=2.55\times 10^3\ m/s[/tex]
So, the speed of the electron is [tex]2.55\times 10^3\ m/s[/tex]. Hence, this is the required solution.
