Answer:
0.0042 is the probability of the stick's weight being 2.33 oz or greater.
Explanation:
We are given the following information in the question:
Mean, μ = 1.75 oz
Standard Deviation, σ = 0.22 oz
We are given that the distribution of drumsticks is a bell shaped distribution that is a normal distribution.
Formula:
[tex]z_{score} = \displaystyle\frac{x-\mu}{\sigma}[/tex]
P(stick's weight being 2.33 oz or greater)
P(x > 2.33)
[tex]P( x > 2.33) = P( z > \displaystyle\frac{2.33 - 1.75}{0.22}) = P(z > 2.6363)[/tex]
[tex]= 1 - P(z \leq 2.6363)[/tex]
Calculation the value from standard normal z table, we have,
[tex]P(x > 2.33) = 1 - 0.9958 =0.0042= 0.42\%[/tex]
0.0042 is the probability of the stick's weight being 2.33 oz or greater.
