Answer: 0.246 A
Explanation: The relationship between the torque experienced by a rectangular current carrying loop, it area and number of turns is given as
T = NAIB cosθ
Where T = torque, A= Area, B= strength of magnetic field, I = Current, N = number of turns
The torque will be maximum when θ is 90°
Hence Tmax = NAIB
N = 250, B= 0.88T
A = length × breadth = 0.04× 0.06 = 0.0024 m², Tmax = 0.13 Nm
0.13 = 250 × 0.0024 ×0.88 × I
0.13 = 0.528 × I
I = 0.13/ 0.528 =0.246 A
Answer:
0.246 A.
Explanation:
Current: This can be defined as the rate of flow of charge in an electric Circuit. The S.I unit of current is Ampere (A).
The expression containing torque, magnetic Field, Current, Area and Number of turns is given as,
τ = BANI.............................. Equation 1
Where τ = Torque, B = Magnetic Field, A = Area, N = Number of Turns, I = current in the coil.
Make I the subject of the equation.
I = τ/BAN....................... Equation 2
Given: τ = 0.13 N.m, B = 0.88 T, N = 250 Turns
But, A = Length(L)×Width(W) = LW
Where L = 4.0 cm = 0.04 m, W = 6.0 cm = 0.06 m
A = 0.04×0.06 = 0.0024 m²
Substitute into equation 2
I = 0.13/(0.88×250×0.0024)
I = 0.13/0.528
I = 0.246 A.
