Respuesta :
Answer:
Option II is right.
Step-by-step explanation:
Given that a line passes through (1, 3) and has a slope of 2 in point-slope form.
We have one point on the line and also the slope
Hence we can use point slope formula for line equation
namely[tex]y-y_1 = m(x-x_1)[/tex]
substitute for points and slope
[tex]y-3=2(x-1)\\[/tex]
is the equation of the line
Answer: point - slope form
y-3=2(x-1)
Step-by-step explanation:
Step 1:-
The equation of the line that passes through the point [tex](x_{1} ,y_{1})[/tex]and having slope 'm' is
[tex](y-y_{1}) = m(x-x_{1} )[/tex]
Given slope m= 2 and the point is [tex](x_{1} ,y_{1})[/tex] = (1,3)
The equation of the line that passes through the point [tex](1 ,3)[/tex]and having slope m=2 is
[tex](y-3) = 2(x-1 )[/tex]
[tex]y-3=2x-2[/tex]
on simplification ,we get
[tex]2x-y=-2+3[/tex]
2x-y=1
The equation of the straight line is 2x-y-1=0
