Answer:
[tex]F = 774146.534\,N[/tex]
Explanation:
The pressure at the bottom of the tank is:
[tex]P_{bottom} = (0.820)\cdot (1000\,\frac{kg}{m^{3}})\cdot (9.807\,\frac{m}{s^{2}})\cdot (30\,ft)\cdot (\frac{0.305\,m}{1\,ft} )[/tex]
[tex]P_{bottom} = 73581.921\,Pa[/tex]
The force exerted on the circular bottom is:
[tex]F=(73581.921\,Pa)\cdot (\frac{\pi}{4} )\cdot [(12\,ft)\cdot (\frac{0.305\,m}{1\,ft} )]^{2}[/tex]
[tex]F = 774146.534\,N[/tex]
