Answer:
k = 138440 N/m
Explanation:
given,
Mass of the car = 1200 Kg
speed of the car = 85 km/h
= 85 x 0.278 = 23.63 m/s
KE of the car
[tex]KE = \dfrac{1}{2} mv^2[/tex]
Using Spring Energy Formula
[tex]KE_{spring}=\dfrac{1}{2}kx^2[/tex]
Using conservation of energy
[tex] \dfrac{1}{2} mv^2=\dfrac{1}{2}kx^2[/tex]
[tex] k = \dfrac{mv^2}{x^2}[/tex]
[tex] k = \dfrac{1200\times 23.63^2}{2.2^2}[/tex]
k = 138440 N/m
Spring stiffness constant of the spring is equal to k = 138440 N/m
