Answer:
[tex]\mu_{k} \approx 0.466[/tex]
Explanation:
As wooden block has a two-dimensional and slides down an inclined plane at constant speed. The following equations of equilibrium are:
[tex]\Sigma F_{x'} = m\cdot g \cdot \sin \theta - \mu_{k}\cdot N = 0[/tex]
[tex]\Sigma F_{y'} = N - m\cdot g \cdot \cos \theta = 0[/tex]
Normal force is:
[tex]N = m\cdot g \cdot \cos \theta[/tex]
Then, it is introduced in the remaining equation, which is simplified afterwards:
[tex]\mu_{k} = \tan \theta[/tex]
[tex]\mu_{k} = \tan 25^{\textdegree}[/tex]
[tex]\mu_{k} \approx 0.466[/tex]
