Answer:
See step by step explanation.
Step-by-step explanation:
Recall that given two integers a, b, a divides b if there exists an integer k such that b = ka.
Let a,b,d be integers, such that d>0.
a) Suppose that d divides a and d divides b. Then, there exists [tex]k_1,k_2 \in \mathbb{Z}[/tex] such that [tex]a = k_1 d [/tex] and [tex]b = k_2 d[/tex]. Consider a+b and a-b. Replacing the previous equation, we have that
[tex]a+b = k_1 d + k_2 d = (k_1+k_2) d [/tex]
[tex]a-b = k_1 d - k_2 d = (k_1-k_2) d[/tex]
Since [tex]k_1,k_2\in \mathbb{Z}[/tex] then [tex]k_1+k_2[/tex] and [tex]k_1-k_2[/tex] are both integers. Then, d divides both a+b and a-b.
b) It is false. Let a = 7, b = 5. Then d = 2 divides a+b (12) and a-b (2) but neither 2 divides 7 nor 2 divides 5.