Respuesta :
Explanation:
Let us assume that W is the weight of the board and [tex]W_{women}[/tex] is the weight of women standing.
And, at the left end supporting force is F and at the right end supporting force is 3F.
So, when this system is in equilibrium then upward force will be equal to the downward force as follows.
[tex]F + 3F = W + W_{women}[/tex]
4F = 100 N + 500 N
F = [tex]\frac{600}{4}[/tex]
= 150 N
For system to be in static friction another condition is that net torque acting on the left end will be equal to zero.
Hence, [tex]\sum \tau[/tex] = 0
[tex](3F \times 8 m) - W (4 m) - W_{women} (8 m)[/tex] = 0
Putting the given values into the above formula as follows.
[tex](3F \times 8 m) - W (4 m) - W_{women} (8 m)[/tex] = 0
[tex](3 \times 150 N \times 8 m) - 100 N (4 m) - 500 N (x)[/tex] = 0
x = 6.4 m
Therefore, at the left side distance from the women is 6.4 m.
And, distance from the right end will be as follows.
8 m - 6.4 m = 1.4 m
