Answer:
The current at time t = 4.00 s is 0.766 A.
Explanation:
Given that,
The quantity of charge through a conductor is modeled as :
[tex]Q=(3t^4-2t+9)\ mC[/tex]
We need to find the current (in A) at time t = 4.00 s. We know that the rate of change of electric charge is called electric current. It is given by :
[tex]I=\dfrac{dQ}{dt}\\\\I=\dfrac{d(3t^4-2t+9)}{dt}\\\\I=12t^3-2[/tex]
At t = 4 s
[tex]I=12(4)^3-2=766\ mC/s\\\\I=0.766\ C/s=0.766\ A[/tex]
So, the current at time t = 4.00 s is 0.766 A. Hence, this is the required solution.
