Answer:
Coefficient in front of the [tex]NO[/tex] in the balanced equation - 4
Explanation:
The unbalanced reaction is shown below as:-
[tex]NH_3+O_2\rightarrow NO+H_2O[/tex]
On the left hand side,
There are 1 nitrogen atom and 3 hydrogen atoms and 3 oxygen atoms
On the right hand side,
There are 1 nitrogen atom and 2 hydrogen atoms and 2 oxygen atoms
Thus,
Right side, [tex]H_2O[/tex] must be multiplied by 6 and [tex]NO[/tex] by 4
Left side, [tex]O_2[/tex] is multiplied by 5 and [tex]NH_3[/tex] by 4 so to balance the whole reaction.
Thus, the balanced reaction is:-
[tex]4NH_3+5O_2\rightarrow 4NO+6H_2O[/tex]
Coefficient in front of the [tex]NO[/tex] in the balanced equation - 4
