Consider the balanced equation. 2HCl + Mg MgCl2 + H2 If 40.0 g of HCl react with an excess of magnesium metal, what is the theoretical yield of hydrogen?

Respuesta :

Answer:

Theoretical yield of hydrogen is 1.11 g

Explanation:

Balanced equation, [tex]Mg+2HCl\rightarrow MgCl_{2}+H_{2}[/tex]

As Mg remain present in excess therefore HCl is the limiting reagent.

According to balanced equation, 2 moles of HCl produce 1 mol of [tex]H_{2}[/tex].

Molar mass of HCl = 36.46 g/mol

So, 40.0 g of HCl = [tex]\frac{40.0}{36.46}moles[/tex] of HCl = 1.10 moles of HCl

Hence, theoretically, number of moles of [tex]H_{2}[/tex] are produced from 1.10 moles of HCl = [tex](\frac{1}{2}\times 1.10)moles=0.550moles[/tex]

Molar mass of [tex]H_{2}[/tex] = 2.016 g/mol

So, theoretical yield of [tex]H_{2}[/tex] = [tex](0.550\times 2.016)g=1.11g[/tex]

Answer:

1.11

Explanation:

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