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choose the point-slope form of the equation below that represents the line that passes through the points (−3, 2) and (2, 1). y 3 = −5(x − 2) y − 2 = −5(x 3) y 3 = −one fifth(x − 2) y − 2 = −one fifth(x 3)

Respuesta :

caylus
Hello,

y-2=(1-2)/(2+3)*(x+3)
==>y-2=-1/5 (x+3)

Answer D

calculista

we know that

the point-slope form of the equation of the line is equal to

[tex] y-y1=m(x-x1) [/tex]

so

Step [tex] 1 [/tex]

Find the slope m

the slope is equal to

[tex] m=\frac{(y2-y1)}{(x2-x1)}[/tex]

Let

[tex] A(-3,2)\\ B(2,1)[/tex]

[tex] m=\frac{(1-2)}{(2+3)}[/tex]

[tex] m=-\frac{1}{5}[/tex]

Step [tex] 2 [/tex]

with m and point A find the equation of the line

[tex] y-2=-\frac{1}{5}(x+3)[/tex]

therefore

the answer is

the point-slope form of the equation is equal to

[tex] y-2=-\frac{1}{5}(x+3)[/tex]


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