Answer:
Step-by-step explanation:
Hello!
The variable of interest is:
X: number of individuals that choose the first wine sample out of 32.
The parameter of interest is the proportion of people that selected the first choise presented.
The sample size is 32 and 22 selected the first option so the sample proportion is p'= 22/32= 0.6875 ≅ 0.69
a.
To estimate the population proportion using a confidence interval you have to use the standard normal approximation:
p' ± [tex]Z_{1-\alpha /2}[/tex] * [tex]\sqrt{\frac{p'(1-p')}{n} }[/tex]
[tex]Z_{1-\alpha 2} = Z_{0.975}= 1.965[/tex]
0.69 ± 1.965*[tex]\sqrt{\frac{0.69*0.31}{32} }[/tex]
[0.529;0.851]
Using a confidence level of 95% you'd expect that the interval [0.529;0.851] contains the population proportion of the subjects that selected the first wine choise presented.
I hope it helps!