Respuesta :
Answer:
Therefore,
Final velocity of the coupled carts after the collision is
[tex]v_{f}=4\ m/s[/tex]
Explanation:
Given:
Mass of Glidding Cart = m₁ = 2 kg
Mass of Stationary Cart = m₂ = 5 kg
Initial velocity of Glidding Cart = u₁ = 14 m/s
Initial velocity of Stationary Cart = u₂ = 0 m/s
To Find:
Final velocity of the coupled carts after the collision = [tex]v_{f}=?[/tex]
Solution:
Law of Conservation of Momentum:
For a collision occurring between two objects in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.
It is denoted by "p" and given by
Momentum = p = mass × velocity
Hence by law of Conservation of Momentum we hame
Momentum before collision = Momentum after collision
Here after collision both are stuck together so both will have same final velocity,
[tex]m_{1}\times u_{1}+m_{2}\times u_{2}=(m_{1}+m_{2})\times v_{f}[/tex]
Substituting the values we get
[tex]2\times 14 + 5\times 0 =(2+5)\times v_{f}[/tex]
[tex]v_{f}=\dfrac{28}{7}=4\ m/s[/tex]
Therefore,
Final velocity of the coupled carts after the collision is
[tex]v_{f}=4\ m/s[/tex]
