Answer:
The total pressure in the new container is 5.608 atm
Explanation:
Step 1: we determine number of moles of N₂ gas present
PV = nRT
Given;
Pressure of N₂ gas = 4.75 atm
Volume of N₂ gas = 1 L
Temperature N₂ gas = 26 ⁰C
R is constant = 0.0821 atm.L/K.mol
n is the number of moles of N₂ gas = ?
[tex]n = \frac{PV}{RT} = \frac{4.75*1}{0.0821*(26+273)} = 0.1935 \ moles \ of \ N_2[/tex]
Step 2: we determine number of moles of O₂ gas present
Given;
Pressure of Given;
Pressure of O₂ gas = 5.25 atm
Volume of O₂ gas = 5 L
Temperature N₂ gas = 20⁰C
n is the number of moles of O₂ gas = ?
[tex]n = \frac{PV}{RT} = \frac{5.25*5}{0.0821*(20+273)} = 1.0912 \ moles \ of \ O_2[/tex]
Step 3: we determine the total pressure of gases in the new container.
Total number of moles of gases = 0.1935 + 1.0912 = 1.2847
Total volume of gases = 1 + 5 = 6L
Total temperature = 26 + 20 = 46 ⁰C
[tex]P_{Total} = \frac{nRT}{V} = \frac{1.2847*0.0821*(46+273)}{6} = 5.608 \ atm[/tex]
Therefore, the total pressure in the new container is 5.608 atm
Answer:
The pressure in the new container is 3.03atm. The pressure is reduced due to a change in volume from smaller containers to a larger container and also due to a reduction in temperature of the containing vessel.
Explanation:
This problem involves the concept of partial pressure of both gases given in the question. In order to find the pressure in the new container assuming ideal gas behavior, we must first calculate the number of moles of each gas in their original container.
From ideal gas law,
PV = nRT
n = PV/RT
For the N2 gas:
P = 4.75atm, V = 1.00L, R = 0.08206atm•L/mol•K, T = 26°C = (26 + 273) = 299K
n = 4.75×1/0.08206× 299
n = 0.194moles
For the O2 gas:
P = 5.25atm, V = 5.00L, R = 0.08206atm•L/mol•K, T = 26°C = (26 + 273) = 299K
n = 5.25×5.00/0.08206× 299
n = 1.07moles
Total number of moles = 0.194 +1.07 = 1.26moles
P = nRT/V
The new container has volume V = 10.0L and temperature T = 20°C = (20 + 273)K = 293K
Therefore,
P = 1.26×0.08206 × 293/10.0 = 3.03atm
the pressure in the new container is 3.03atm.
